Find the equations of the sides QR and RP of | vedclass

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(C) $1$. For side $QR$: It passes through the origin $(0, 0)$ with slope $m_1 = \frac{2}{\sqrt{3}}$. The equation is $y - 0 = \frac{2}{\sqrt{3}}(x - 0

Vedclass · Accepted Answer

$y = \frac{2}{\sqrt{3}}x, y = -\frac{2}{\sqrt{3}}x + \frac{4}{\sqrt{3}} + 1$

Vedclass · Answer

(C) $1$. For side $QR$: It passes through the origin $(0, 0)$ with slope $m_1 = \frac{2}{\sqrt{3}}$. The equation is $y - 0 = \frac{2}{\sqrt{3}}(x - 0)$,which simplifies to $y = \frac{2}{\sqrt{3}}x$.$2$. For side $RP$: It passes through point $P(2, 1)$ with slope $m_2 = -\frac{2}{\sqrt{3}}$. The equation is $y - 1 = -\frac{2}{\sqrt{3}}(x - 2)$.$3$. Simplifying the equation for $RP$: $y - 1 = -\frac{2}{\sqrt{3}}x + \frac{4}{\sqrt{3}}$,which gives $y = -\frac{2}{\sqrt{3}}x + \frac{4}{\sqrt{3}} + 1$.

Find the equations of the sides $QR$ and $RP$ of a triangle $PQR$ where $P = (2, 1)$,and the sides $QR$ and $RP$ have slopes $m_1 = \frac{2}{\sqrt{3}}$ and $m_2 = -\frac{2}{\sqrt{3}}$ respectively,passing through the origin $(0, 0)$ for $QR$ and intersecting at $P(2, 1)$ for $RP$.

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