Find the current in the circuit. (in A) | vedclass

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(D) The given circuit consists of two batteries and four resistors. First, calculate the equivalent resistance of the circuit. The two $100 \, \Omega$

Vedclass · Accepted Answer

$0.04$

Vedclass · Answer

(D) The given circuit consists of two batteries and four resistors. First, calculate the equivalent resistance of the circuit. The two $100 \, \Omega$ resistors are connected in parallel. Their equivalent resistance is $R_p = \frac{100 	imes 100}{100 + 100} = 50 \, \Omega$. These are in series with two other $100 \, \Omega$ resistors. Thus, the total equivalent resistance is $R_{eq} = 50 \, \Omega + 100 \, \Omega + 100 \, \Omega = 250 \, \Omega$. The two batteries of $20 \, V$ and $10 \, V$ are connected in opposition (positive terminals facing each other). Therefore, the net electromotive force (emf) is $E_{net} = 20 \, V - 10 \, V = 10 \, V$. Using Ohm's law, the current in the circuit is $I = \frac{E_{net}}{R_{eq}} = \frac{10 \, V}{250 \, \Omega} = 0.04 \, A$.

Find the current in the circuit. (in $ A$)

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