Find the charge on the capacitor C in the fol | vedclass

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(D) At steady state,no current flows through the branch containing the capacitor. Therefore,the capacitor acts as an open circuit.The circuit simplifi

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$18$

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(D) At steady state,no current flows through the branch containing the capacitor. Therefore,the capacitor acts as an open circuit.The circuit simplifies to a series combination of the $12 	ext{ V}$ battery,the $2 \Omega$ resistor,and the $6 \Omega$ resistor.The total resistance of the circuit is $R_{eq} = 2 \Omega + 6 \Omega = 8 \Omega$.The current flowing through the circuit is $I = \frac{V}{R_{eq}} = \frac{12 	ext{ V}}{8 \Omega} = 1.5 	ext{ A}$.The voltage across the capacitor is equal to the voltage across the $6 \Omega$ resistor because they are connected in parallel across the same nodes.$V_C = I 	imes 6 \Omega = 1.5 	ext{ A} 	imes 6 \Omega = 9 	ext{ V}$.The charge on the capacitor is $q = C 	imes V_C$.Given $C = 2 \mu 	ext{F}$,we have $q = 2 \mu 	ext{F} 	imes 9 	ext{ V} = 18 \mu 	ext{C}$.

Find the charge on the capacitor $C$ in the following circuit in $\mu C$.

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