Find the charge on capacitor $C_3$. Given that $C_1 = C_2 = C$ and $C_3 = C_4 = 3C$.

  • A
    $\frac{3}{2} CV$
  • B
    $\frac{C V}{2}$
  • C
    $3 CV$
  • D
    $2 CV$

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Four identical thin, square metal sheets, $S_1, S_2, S_3$, and $S_4$, each of side $a$ are kept parallel to each other with equal distance $d( < < a)$ between them, as shown in the figure. Let $C_0 = \varepsilon_0 a^2 / d$, where $\varepsilon_0$ is the permittivity of free space.
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$List-I$$List-II$
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$(Q)$ The capacitance between $S_1$ and $S_4$, with $S_2$ shorted to $S_3$, is$(2)$ $C_0 / 2$
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$(S)$ The capacitance between $S_1$ and $S_2$, with $S_3$ shorted to $S_1$, and $S_2$ shorted to $S_4$, is$(4)$ $2 C_0 / 3$
$(5)$ $2 C_0$

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If the charge on a capacitor is increased by $2 \ C$,the energy stored in it increases by $21\%$. The original charge on the capacitor is....$C$

Charge on the capacitor in the given circuit in steady state condition is :- ............... $\mu C$

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