Find the center of mass (x,y,z) of the follow | vedclass

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First we find the center of mass of each cube. It is located by symmetry: $(0.5,0.5,0.5)$ $(1.5,0.5,0.5),(0.5,1.5,0.5),(0.5,0.5,1.5)$

Now we find t

Vedclass · Accepted Answer

$(3/4,3/4,3/4)$

Vedclass · Answer

First we find the center of mass of each cube. It is located by symmetry: $(0.5,0.5,0.5)$ $(1.5,0.5,0.5),(0.5,1.5,0.5),(0.5,0.5,1.5)$

Now we find the center of mass by treating the $COM$ of each cube as a point particle$:$

$x_{	ext {COM }}=\frac{0.5+1.5+0.5+0.5}{4}=0.75$

$y_{COM}=\frac{0.5+0.5+1.5+0.5}{4}=0.75$

$z_{	ext {COM}}=\frac{0.5+0.5+0.5+1.5}{4}=0.75$

Find the center of mass $(x,y,z)$ of the following structure of four identical cubes if the length of each side of a cube is $1$ unit.

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