Find the amount of water displaced by a solid | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The amount of water displaced by a solid spherical ball is equal to the volume of the solid spherical ball.The diameter of the ball is $d = 4.2 \,

Vedclass · Accepted Answer

$38.808$

Vedclass · Answer

(D) The amount of water displaced by a solid spherical ball is equal to the volume of the solid spherical ball.The diameter of the ball is $d = 4.2 \, cm$,so the radius is $r = \frac{d}{2} = \frac{4.2}{2} = 2.1 \, cm$.The volume of a sphere is given by the formula $V = \frac{4}{3} \pi r^3$.Substituting the values: $V = \frac{4}{3} 	imes \frac{22}{7} 	imes (2.1)^3$.$V = \frac{4}{3} 	imes \frac{22}{7} 	imes 2.1 	imes 2.1 	imes 2.1$.$V = 4 	imes \frac{22}{7} 	imes 0.7 	imes 2.1 	imes 2.1$.$V = 4 	imes 22 	imes 0.1 	imes 2.1 	imes 2.1 = 88 	imes 0.1 	imes 4.41 = 8.8 	imes 4.41 = 38.808 \, cm^3$.Thus,the amount of water displaced is $38.808 \, cm^3$.

Find the amount of water displaced by a solid spherical ball of diameter $4.2 \, cm$,when it is completely immersed in water. (in $, cm^3$)

Similar Questions

Find the surface area of a sphere of diameter $49\, cm$ (in $cm^2$).

The diameter of a solid hemisphere is $7 \, cm$. Find its curved surface area and total surface area (in $cm^2$).

The curved surface area of a cylinder is $550 \, cm^2$. If its height is $50 \, cm$,find its diameter in $cm$.

$1\, m^{3} = \dots \, cm^{3}$

$A$ heap of wheat is in the form of a cone whose diameter is $42 \, m$ and height is $20 \, m$. The heap is to be covered by canvas to protect it from rain. If the price of canvas is $₹ 75$ per $m^2$,find the cost of the canvas required.

Vedclass Test Series

Exam Paper Generator

Online Exam Module