Find the HCF and LCM of 6 and 20 using the pr | vedclass

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(A) Step $1$: Find the prime factorization of the given numbers.$6 = 2 	imes 3$$20 = 2^2 	imes 5$Step $2$: To find the $HCF$,take the product of the

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$HCF$ = $2$,$LCM$ = $60$

Vedclass · Answer

(A) Step $1$: Find the prime factorization of the given numbers.$6 = 2 	imes 3$$20 = 2^2 	imes 5$Step $2$: To find the $HCF$,take the product of the smallest power of each common prime factor.Common prime factor is $2$. The smallest power is $2^1$.Therefore,$HCF$ = $2$.Step $3$: To find the $LCM$,take the product of the highest power of each prime factor involved.Prime factors involved are $2, 3,$ and $5$.Highest powers are $2^2, 3^1,$ and $5^1$.$LCM$ = $2^2 	imes 3^1 	imes 5^1 = 4 	imes 3 	imes 5 = 60$.Thus,$HCF$ = $2$ and $LCM$ = $60$.

Find the $HCF$ and $LCM$ of $6$ and $20$ using the prime factorization method.

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