Find the 20^{th} term of the A.P. -40, -15, 1 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The given $A.P.$ is $-40, -15, 10, \ldots$Here,the first term $a = -40$.The common difference $d = -15 - (-40) = -15 + 40 = 25$.The formula for th

Vedclass · Accepted Answer

$435$

Vedclass · Answer

(D) The given $A.P.$ is $-40, -15, 10, \ldots$Here,the first term $a = -40$.The common difference $d = -15 - (-40) = -15 + 40 = 25$.The formula for the $n^{th}$ term of an $A.P.$ is $a_n = a + (n - 1)d$.To find the $20^{th}$ term $(n = 20)$:$a_{20} = -40 + (20 - 1) 	imes 25$$a_{20} = -40 + 19 	imes 25$$a_{20} = -40 + 475$$a_{20} = 435$.Therefore,the $20^{th}$ term is $435$.

Find the $20^{th}$ term of the $A.P.$ $-40, -15, 10, \ldots$

Similar Questions

Find the sum of the first $n$ terms of the $A.P.$ $5, 2, -1, \ldots$

Verify that each of the following is an $AP$,and then write its next three terms.
$a, 2a+1, 3a+2, 4a+3, \ldots$

Solve the equation $-4 + (-1) + 2 + \ldots + x = 437$.

Split $207$ into three parts such that these are in $AP$ and the product of the two smaller parts is $4623$.

Find the sum of those integers from $1$ to $500$ which are multiples of $2$ as well as of $5$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module