Find the HCF of 96 and 404 by the prime facto | vedclass

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(B) The prime factorisation of $96$ and $404$ is as follows:$96 = 2^5 	imes 3$$404 = 2^2 	imes 101$The $HCF$ is the product of the smallest power of

Vedclass · Accepted Answer

$9696$

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(B) The prime factorisation of $96$ and $404$ is as follows:$96 = 2^5 	imes 3$$404 = 2^2 	imes 101$The $HCF$ is the product of the smallest power of each common prime factor in the numbers:$HCF(96, 404) = 2^2 = 4$Using the relationship $LCM(a, b) 	imes HCF(a, b) = a 	imes b$:$LCM(96, 404) = \frac{96 	imes 404}{HCF(96, 404)}$$LCM(96, 404) = \frac{96 	imes 404}{4}$$LCM(96, 404) = 96 	imes 101 = 9696$

Find the $HCF$ of $96$ and $404$ by the prime factorisation method. Hence,find their $LCM$.

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