Find the potential difference across the 24,O | vedclass

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(B) First,calculate the equivalent resistance $(R_p)$ of the parallel combination of resistors: $48\,\Omega, 48\,\Omega, 24\,\Omega, 6\,\Omega, 4\,\Om

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$2$

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(B) First,calculate the equivalent resistance $(R_p)$ of the parallel combination of resistors: $48\,\Omega, 48\,\Omega, 24\,\Omega, 6\,\Omega, 4\,\Omega,$ and $2\,\Omega$.$\frac{1}{R_p} = \frac{1}{48} + \frac{1}{48} + \frac{1}{24} + \frac{1}{6} + \frac{1}{4} + \frac{1}{2}$$\frac{1}{R_p} = \frac{1 + 1 + 2 + 8 + 12 + 24}{48} = \frac{48}{48} = 1\,\Omega$So,$R_p = 1\,\Omega$.The total current flowing through the circuit is $I = 2\,A$.The potential difference across the parallel combination is $V = I 	imes R_p = 2\,A 	imes 1\,\Omega = 2\,V$.Since all resistors in the parallel combination are connected across the same two points,the potential difference across each of them,including the $24\,\Omega$ resistor,is $2\,V$.

Find the potential difference across the $24\,\Omega$ resistor in the given circuit.

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