Consider the situation shown in the figure. T | vedclass

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(B) The induced electromotive force $(emf)$ in a moving conductor is given by $e = B l v$,where $B$ is the magnetic field,$l$ is the length of the con

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Remain the same

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(B) The induced electromotive force $(emf)$ in a moving conductor is given by $e = B l v$,where $B$ is the magnetic field,$l$ is the length of the conductor perpendicular to the velocity,and $v$ is the velocity.In this setup,the effective length $l$ of the wire that cuts the magnetic field lines is the distance between the two rails (the chord length of the wire).When the straight wire $AB$ is replaced by a semicircular wire with the same chord length,the effective length $l$ remains unchanged because the distance between the points of contact on the rails remains the same.Since $e = B l v$,and $B, l,$ and $v$ remain constant,the induced $emf$ remains the same.Consequently,the induced current $I = e / R$ also remains the same,assuming the resistance $R$ of the circuit does not change.

Consider the situation shown in the figure. The wire $AB$ is sliding on the fixed rails with a constant velocity $v$. If the wire $AB$ is replaced by a semicircular wire of the same chord length,the magnitude of the induced current will

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