Find magnetic field at centre $P$ if length of side of square loop is $20\, cm$
$12 \sqrt{2} \times 10^{-6} T$
$12 \times 10^{-6} T$
$6 \times 10^{-6} T$
$6 \sqrt{2} \times 10^{-6} T$
A current $I$ flowing through the loop as shown in the adjoining figure. The magnetic field at centre $O$ is
A length $L$ of wire carries a steady current $I$. It is bent first to form a circular plane coil of one turn. The same length is now bent more sharply to give a double loop of smaller radius. The magnetic field at the centre caused by the same current is
A portion of a conductive wire is bent in the form of a semicircle of radius $r$ as shown below in fig. At the centre of semicircle, the magnetic induction will be
Give differences between Biot-Savart law and Coulomb’s law.