Find a relation between $x$ and $y$ if the points $(x, y), (1, 2)$ and $(7, 0)$ are collinear.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) If the given points are collinear,then the area of the triangle formed by these points must be $0$.
The area of a triangle with vertices $(x_1, y_1), (x_2, y_2)$ and $(x_3, y_3)$ is given by the formula:
Area $= \frac{1}{2} |x_1(y_2 - y_3) + x_2(y_3 - y_1) + x_3(y_1 - y_2)|$
Substituting the given points $(x, y), (1, 2)$ and $(7, 0)$ into the formula:
$0 = \frac{1}{2} |x(2 - 0) + 1(0 - y) + 7(y - 2)|$
$0 = \frac{1}{2} |2x - y + 7y - 14|$
$0 = \frac{1}{2} |2x + 6y - 14|$
Multiplying by $2$ on both sides:
$2x + 6y - 14 = 0$
Dividing the entire equation by $2$:
$x + 3y - 7 = 0$
Thus,the required relation between $x$ and $y$ is $x + 3y - 7 = 0$.

Explore More

Similar Questions

The vertices of a $\Delta ABC$ are $A(4, 6)$,$B(1, 5)$,and $C(7, 2)$. $A$ line is drawn to intersect sides $AB$ and $AC$ at $D$ and $E$ respectively,such that $\frac{AD}{AB} = \frac{AE}{AC} = \frac{1}{4}$. Calculate the area of $\Delta ADE$ and compare it with the area of $\Delta ABC$.

Difficult
View Solution

Find a relation between $x$ and $y$ such that the point $(x, y)$ is equidistant from the point $(3, 6)$ and $(-3, 4)$.

Find a relation between $x$ and $y$ such that the point $(x, y)$ is equidistant from the points $(7, 1)$ and $(3, 5)$.

Find the values of $y$ for which the distance between the points $P(2, -3)$ and $Q(10, y)$ is $10$ units.

Find the coordinates of the point which divides the line segment joining the points $(-1, 7)$ and $(4, -3)$ in the ratio $2:3$.

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo