Find AB, if A = begin{bmatrix} 0 & -1 0 & 2 | vedclass

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(A) Given $A = \begin{bmatrix} 0 & -1 \ 0 & 2 \end{bmatrix}$ and $B = \begin{bmatrix} 3 & 5 \ 0 & 0 \end{bmatrix}$.To find $AB$,we perform matrix mu

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$\begin{bmatrix} 0 & 0 \ 0 & 0 \end{bmatrix}$

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(A) Given $A = \begin{bmatrix} 0 & -1 \ 0 & 2 \end{bmatrix}$ and $B = \begin{bmatrix} 3 & 5 \ 0 & 0 \end{bmatrix}$.To find $AB$,we perform matrix multiplication:$AB = \begin{bmatrix} 0 & -1 \ 0 & 2 \end{bmatrix} \begin{bmatrix} 3 & 5 \ 0 & 0 \end{bmatrix}$$AB = \begin{bmatrix} (0 	imes 3) + (-1 	imes 0) & (0 	imes 5) + (-1 	imes 0) \ (0 	imes 3) + (2 	imes 0) & (0 	imes 5) + (2 	imes 0) \end{bmatrix}$$AB = \begin{bmatrix} 0 + 0 & 0 + 0 \ 0 + 0 & 0 + 0 \end{bmatrix} = \begin{bmatrix} 0 & 0 \ 0 & 0 \end{bmatrix}$.Thus,the product $AB$ is the zero matrix $\begin{bmatrix} 0 & 0 \ 0 & 0 \end{bmatrix}$.

Find $AB,$ if $A = \begin{bmatrix} 0 & -1 \\ 0 & 2 \end{bmatrix}$ and $B = \begin{bmatrix} 3 & 5 \\ 0 & 0 \end{bmatrix}$.

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