Find AB, if A=left[begin{array}{ll}6 & 9 2 & | vedclass

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(A) The matrix $A$ has $2$ columns,which is equal to the number of rows of matrix $B$. Therefore,the product $AB$ is defined.$AB = \left[\begin{array}

Vedclass · Accepted Answer

$\left[\begin{array}{ccc}75 & 117 & 72 \ 25 & 39 & 24\end{array}ight]$

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(A) The matrix $A$ has $2$ columns,which is equal to the number of rows of matrix $B$. Therefore,the product $AB$ is defined.$AB = \left[\begin{array}{ll}6 & 9 \ 2 & 3\end{array}ight] \left[\begin{array}{lll}2 & 6 & 0 \ 7 & 9 & 8\end{array}ight]$$AB = \left[\begin{array}{lll}6(2)+9(7) & 6(6)+9(9) & 6(0)+9(8) \ 2(2)+3(7) & 2(6)+3(9) & 2(0)+3(8)\end{array}ight]$$AB = \left[\begin{array}{lll}12+63 & 36+81 & 0+72 \ 4+21 & 12+27 & 0+24\end{array}ight]$$AB = \left[\begin{array}{ccc}75 & 117 & 72 \ 25 & 39 & 24\end{array}ight]$

Find $AB,$ if $A=\left[\begin{array}{ll}6 & 9 \\ 2 & 3\end{array}\right]$ and $B=\left[\begin{array}{lll}2 & 6 & 0 \\ 7 & 9 & 8\end{array}\right].$

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