Find the value of V_{AB} in the given circuit | vedclass

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(A) In the given circuit, the diode is in forward bias, so it acts as a short circuit (assuming an ideal diode).The circuit consists of a $30 \, V$ ba

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$10 \, V$

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(A) In the given circuit, the diode is in forward bias, so it acts as a short circuit (assuming an ideal diode).The circuit consists of a $30 \, V$ battery connected to a $10 \, \Omega$ resistor in series with a parallel combination of two $10 \, \Omega$ resistors.The equivalent resistance of the two $10 \, \Omega$ resistors in parallel is $R_p = \frac{10 	imes 10}{10 + 10} = 5 \, \Omega$.Now, the circuit is a series combination of a $10 \, \Omega$ resistor and a $5 \, \Omega$ equivalent resistor across a $30 \, V$ source.The voltage $V_{AB}$ is the voltage across the parallel combination of $5 \, \Omega$.Using the voltage divider rule:$V_{AB} = \left( \frac{R_p}{R_1 + R_p} ight) 	imes V_{total}$$V_{AB} = \left( \frac{5}{10 + 5} ight) 	imes 30$$V_{AB} = \left( \frac{5}{15} ight) 	imes 30 = \frac{1}{3} 	imes 30 = 10 \, V$.

Find the value of $V_{AB}$ in the given circuit.

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