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(B) Step $1$: Reaction of $1,2$-dimethylcyclohexane with $Br_2/h
u$ (free radical bromination) leads to the formation of $1$-bromo-$1,2$-dimethylcycl

Vedclass · Accepted Answer

Octane$-2,7-$dione

Vedclass · Answer

(B) Step $1$: Reaction of $1,2$-dimethylcyclohexane with $Br_2/h
u$ (free radical bromination) leads to the formation of $1$-bromo-$1,2$-dimethylcyclohexane (compound $A$).Step $2$: Treatment of $A$ with $CH_3ONa$ (a strong base) results in dehydrobromination via an $E2$ mechanism to form $1,2$-dimethylcyclohex$-1-$ene (compound $B$).Step $3$: Ozonolysis of $1,2$-dimethylcyclohex$-1-$ene $(B)$ followed by reductive workup with $Zn/H_2O$ cleaves the double bond to yield $2,7$-octanedione (compound $C$).

The final product $'C'$ is?

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