The figure shows a two-block system. A 4 ,kg | vedclass

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(B) $1$. Assume both blocks move together with a common acceleration $a$. The total mass of the system is $M = 4 \,kg + 2 \,kg = 6 \,kg$.$2$. The exte

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$5$

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(B) $1$. Assume both blocks move together with a common acceleration $a$. The total mass of the system is $M = 4 \,kg + 2 \,kg = 6 \,kg$.$2$. The external force applied is $F = 30 \,N$. The common acceleration is $a = F / M = 30 / 6 = 5 \,m/s^2$.$3$. To check if they move together,we calculate the required frictional force $f$ on the $2 \,kg$ block: $f = m \cdot a = 2 \,kg 	imes 5 \,m/s^2 = 10 \,N$.$4$. The limiting friction $f_L$ between the blocks is $f_L = \mu_s \cdot N = \mu_s \cdot (m \cdot g) = 0.8 	imes 2 	imes 10 = 16 \,N$.$5$. Since the required frictional force $(10 \,N)$ is less than the limiting friction $(16 \,N)$,the blocks will move together with an acceleration of $5 \,m/s^2$.

Similar Questions

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