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(D) For total internal reflection to occur at the surface,the angle of incidence must be greater than or equal to the critical angle $	heta_c$.Given

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(D) For total internal reflection to occur at the surface,the angle of incidence must be greater than or equal to the critical angle $	heta_c$.Given the refractive index $\mu = 2$,the critical angle $	heta_c$ is calculated as:$\sin 	heta_c = \frac{1}{\mu} = \frac{1}{2}$$	heta_c = 30^{\circ}$To ensure no light passes through the segment $AB$,any light ray originating from the source $S$ and striking the surface $AB$ must have an angle of incidence greater than or equal to $	heta_c = 30^{\circ}$.This implies that the source $S$ must be located within a region such that the angle subtended by the segment $AB$ at $S$ is less than or equal to the critical angle,or more specifically,the rays reaching $AB$ from $S$ must strike at angles $\ge 	heta_c$. The shaded region in the diagrams represents the set of points where this condition is satisfied. Based on the geometry,the correct representation is given by option $D$.

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