Figure (a) shows a plot of voltage across the | vedclass

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(B) The quality factor $Q$ is defined as $Q = \frac{\omega_0 L}{R} = \frac{1}{R} \sqrt{\frac{L}{C}}$.Higher $Q$ implies a sharper resonance peak in th

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Graph $(1)$ corresponds to graph $(c)$

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(B) The quality factor $Q$ is defined as $Q = \frac{\omega_0 L}{R} = \frac{1}{R} \sqrt{\frac{L}{C}}$.Higher $Q$ implies a sharper resonance peak in the voltage vs frequency graph (figure $a$) and a steeper change in the phase angle $\phi$ near resonance (figure $b$).In figure $(a)$,graph $(1)$ is the sharpest,indicating the highest $Q$ value. Graph $(3)$ is the broadest,indicating the lowest $Q$ value.In figure $(b)$,graph $(c)$ shows the steepest change in phase angle near $\omega / \omega_0 = 1$,corresponding to the highest $Q$. Graph $(a)$ shows the shallowest change,corresponding to the lowest $Q$.Therefore,graph $(1)$ matches graph $(c)$,graph $(2)$ matches graph $(b)$,and graph $(3)$ matches graph $(a)$.Thus,the statement 'Graph $(1)$ corresponds to graph $(c)$' is correct.

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