The figure shows a stationary wave between tw | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) In a stationary wave,all particles within a single loop vibrate in the same phase. Particles in adjacent loops vibrate in opposite phases (a phase

Vedclass · Accepted Answer

$2$ and $3$ only

Vedclass · Answer

(C) In a stationary wave,all particles within a single loop vibrate in the same phase. Particles in adjacent loops vibrate in opposite phases (a phase difference of $\pi$ radians).Point $X$ is in the first loop.Point $1$ is in the second loop,which is adjacent to the first loop. Therefore,point $1$ is in opposite phase to $X$.Point $2$ and point $3$ are in the third loop. Since the third loop is separated from the first loop by one loop (the second loop),the phase difference between the first and third loop is $2\pi$ radians,which is equivalent to being in the same phase.Thus,points $2$ and $3$ are in phase with point $X$.

The figure shows a stationary wave between two fixed points $P$ and $Q$. Which point$(s)$ among $1, 2,$ and $3$ are in phase with point $X$?

Similar Questions

$A$ wave travels on a light string. The equation of the wave is $Y = A \sin (kx - \omega t + 30^o)$. It is reflected from a heavy string tied to an end of the light string at $x = 0$. If $64\%$ of the incident energy is reflected,the equation of the reflected wave is:

The equation of a stationary wave is $Y = 10 \sin \left( \frac{\pi x}{4} \right) \cos (20 \pi t)$. The distance between two consecutive nodes in metres is

From the given progressive wave equations,which waves are used to produce a standing wave?
$z_1 = A \cos(\omega t - kx)$
$z_2 = A \cos(\omega t + kx)$
$z_3 = A \cos(\omega t + ky)$
$z_4 = A \cos(2\omega t - 2ky)$

Standing waves can be produced:

Stationary waves can be produced in

Vedclass Test Series

Exam Paper Generator

Online Exam Module