Factorise of the following : $64 a^{3}-27 b^{3}-144 a^{2} b+108 a b^{2}$
Factorise of the following : $64 a^{3}-27 b^{3}-144 a^{2} b+108 a b^{2}$
$64 a^{3}-27 b^{3}-144 a^{2} b+108 a b^{2}=(4 a)^{3}-(3 b)^{3}-3(4 a)(3 b)[4 a-3 b]$
$=(4 a-3 b)^{3}$ $[$ Using Identity $VII]$
$=(4 a-3 b)(4 a-3 b)(4 a-3 b)$
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