Explain the Law of Dominance using a monohybrid cross.
Explain the Law of Dominance using a monohybrid cross.
Mendel's law of dominance states that a dominant allele expresses itself in a monohybrid cross and suppresses the expression of recessive allele. However, this recessive allele for a character is not lost and remains hidden or masked in the progenies of $\mathrm{F}_{1}$ generation and reappears in the next generation.
For example, when pea plants with round seeds $(RR)$ are crossed with plants with wrinkled seeds $(rr)$, all seeds in $\mathrm{F}_{1}$, generation were found to be round $(Rr)$. When these round seeds were self-fertilized, both the round and wrinkled seeds appeared in $\mathrm{F}_{2}$ generation in $3: 1$ ratio. Hence, in $\mathrm{F}_{1}$ generation, the dominant character (round seeds) appeared and the recessive character (wrinkled seeds) got suppressed, which reappeared in $\mathrm{F}_{2}$ generation. (figure)
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Mendel cross tall and dwarf plant. In $F_{2}$-generation the observed ratio was $3: 1$ (tall: short). From this result, he deduced
$I.$ law of dominance
$II.$ law of independent assortment
$III.$ law of segregation
$IV.$ incomplete dominance
Choose the correct option
Mendel cross tall and dwarf plant. In $F_{2}$-generation the observed ratio was $3: 1$ (tall: short). From this result, he deduced
$I.$ law of dominance
$II.$ law of independent assortment
$III.$ law of segregation
$IV.$ incomplete dominance
Choose the correct option
Which of the following is genotypic ratio of Mendel's monohybrid cross
Which of the following is genotypic ratio of Mendel's monohybrid cross
$BB =$ for black colour alleles
$bb =$ for brown colour alleles
Offspring of a cross between a black mouse and brown mouse allowed to interbreed than find out the percentage of black coat in them
$BB =$ for black colour alleles
$bb =$ for brown colour alleles
Offspring of a cross between a black mouse and brown mouse allowed to interbreed than find out the percentage of black coat in them