Explain the Law of Dominance using a monohybrid cross.
Mendel's law of dominance states that a dominant allele expresses itself in a monohybrid cross and suppresses the expression of recessive allele. However, this recessive allele for a character is not lost and remains hidden or masked in the progenies of $\mathrm{F}_{1}$ generation and reappears in the next generation.
For example, when pea plants with round seeds $(RR)$ are crossed with plants with wrinkled seeds $(rr)$, all seeds in $\mathrm{F}_{1}$, generation were found to be round $(Rr)$. When these round seeds were self-fertilized, both the round and wrinkled seeds appeared in $\mathrm{F}_{2}$ generation in $3: 1$ ratio. Hence, in $\mathrm{F}_{1}$ generation, the dominant character (round seeds) appeared and the recessive character (wrinkled seeds) got suppressed, which reappeared in $\mathrm{F}_{2}$ generation. (figure)
A true breeding plant producing red flowers is crossed with a pure plant producing white flowers. Allele for red colour of flower is dominant. After selfing the plants of first filial generation, the proportion of plants producing red and white flowers in the progeny would be
Mating of an organism to a double recessive in order to determine whether it is homozygous or heterozygous for a character under consideration, is called
Mendel cross tall and dwarf plant. In $F_{2}$-generation the observed ratio was $3: 1$ (tall: short). From this result, he deduced
$I.$ law of dominance
$II.$ law of independent assortment
$III.$ law of segregation
$IV.$ incomplete dominance
Choose the correct option
Which of the following is genotypic ratio of Mendel's monohybrid cross
$BB =$ for black colour alleles
$bb =$ for brown colour alleles
Offspring of a cross between a black mouse and brown mouse allowed to interbreed than find out the percentage of black coat in them