Explain linear charge density, surface charge density and volume charge density for uniform charge distribution.
Linear charge density $(\lambda):$ Amount of charge per unit length is called linear charge density $(\lambda)$. $\lambda=\frac{\text { Total charge on line }}{\text { length of line }}=\frac{Q}{l}$
Unit : $\mathrm{C} / \mathrm{m}$ Dimensional formula : $\mathrm{M}^{0} \mathrm{~L}^{-1} \mathrm{~T}^{1} \mathrm{~A}^{1}$
Surface charge density $(\sigma)$ : Amount of charge per unit area is called surface charge density $(\sigma)$. $\sigma=\frac{\text { Total charge on surface }}{\text { Area of surface }}=\frac{Q}{A}$
Unit: $\mathrm{C} / \mathrm{m}^{2}$ Dimensional formula : $\mathrm{M}^{0} \mathrm{~L}^{-2} \mathrm{~T}^{1} \mathrm{~A}^{1}$
Volume charge density $(\rho)$ : Amount of charge per unit volume is called volume charge density $(\rho)$. $\rho=\frac{\text { Total charge on volume }}{\text { Volume }}=\frac{Q}{V}$
Unit : $\frac{C}{m^{3}}$ Dimensional formula : $\mathrm{M}^{0} \mathrm{~L}^{-3} \mathrm{~T}^{1} \mathrm{~A}^{1}$
What are linear, surface and volume distribution of charge ?
If a metal cube of side $5\, cm$ has a charge of $6$ microcoulombs, then the surface charge density is
A solid sphere of radius $R_1$ and volume charge density $\rho = \frac{{{\rho _0}}}{r}$ is enclosed by a hollow sphere of radius $R_2$ with negative surface charge density $\sigma $, such that the total charge in the system is zero. $\rho_0$ is a positive constant and $r$ is the distance from the centre of the sphere. The ratio $R_2/R_1$ is
Three concentric metallic spherical shells of radii $R, 2 R, 3 R$, are given charges $Q_1, Q_2, Q_3$, respectively. It is found that the surface charge densities on the outer surfaces of the shells are equal. Then, the ratio of the charges given to the shells, $Q_1: Q_2: Q_3$, is
A semicircular ring of radius $'a'$ has charge density $\lambda = {\lambda _0}\,\cos \,\theta $ where ${\lambda _0}$ is constant and $'\theta'$ is shown in figure. Then total charge on the ring is