Excess of KI reacts with CuSO_4 solution and | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The reaction between $KI$ and $CuSO_4$ is: $2CuSO_4 + 4KI 	o Cu_2I_2 + I_2 + 2K_2SO_4$. In this reaction,$Cu^{2+}$ is reduced to $Cu^+$ (forming

Vedclass · Accepted Answer

$CuI_2$ is formed

Vedclass · Answer

(B) The reaction between $KI$ and $CuSO_4$ is: $2CuSO_4 + 4KI 	o Cu_2I_2 + I_2 + 2K_2SO_4$. In this reaction,$Cu^{2+}$ is reduced to $Cu^+$ (forming $Cu_2I_2$) and $I^-$ is oxidized to $I_2$. Then,$I_2$ reacts with $Na_2S_2O_3$: $I_2 + 2Na_2S_2O_3 	o Na_2S_4O_6 + 2NaI$. Here,$Na_2S_2O_3$ is oxidized to $Na_2S_4O_6$ and $I_2$ is reduced to $I^-$. $CuI_2$ is not formed because $Cu^{2+}$ oxidizes $I^-$ to $I_2$ immediately,resulting in the formation of $Cu_2I_2$ (cuprous iodide).

Excess of $KI$ reacts with $CuSO_4$ solution and then $Na_2S_2O_3$ solution is added to it. Which of the statements is incorrect for this reaction?

Similar Questions

Complete the following reactions:
$(a)$ $4FeCr_2O_4 + 8Na_2CO_3 + 7O_2 \to 8Na_2CrO_4 + 2Fe_2O_3 + 8CO_2$
$(b)$ $2Na_2CrO_4 + 2H^+ \to Na_2Cr_2O_7 + 2Na^+ + H_2O$
Identify the species $X$ in both reactions.

Which transition element of the $3d$ series is used in a dry battery cell?

Compounds of $d-$block elements can stabilize in higher oxidation states only with $F$ and $O$. Which statement is incorrect?

Which one of the following species is stable in aqueous solution?

What is the starting material for the preparation of $KMnO_4$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module