Examine whether the following equation is qua | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) quadratic equation in the variable $x$ is an equation of the form $ax^{2} + bx + c = 0$,where $a, b, c$ are real numbers and $a 
eq 0$. The expon

Vedclass · Accepted Answer

No,it is not a quadratic equation.

Vedclass · Answer

(B) quadratic equation in the variable $x$ is an equation of the form $ax^{2} + bx + c = 0$,where $a, b, c$ are real numbers and $a 
eq 0$. The exponent of the variable $x$ must be a non-negative integer.Given equation: $x^{2} + 2\sqrt{x} + 3 = 0$.We can rewrite the term $\sqrt{x}$ as $x^{\frac{1}{2}}$.So,the equation becomes $x^{2} + 2x^{\frac{1}{2}} + 3 = 0$.In this equation,the exponent of $x$ in the second term is $\frac{1}{2}$,which is not a whole number (non-negative integer).Since the variable $x$ does not have a power of $2$ as its highest degree with integer exponents,the given equation is not a polynomial,and therefore,it is not a quadratic equation.

Examine whether the following equation is quadratic or not: $x^{2}+2 \sqrt{x}+3=0$

Similar Questions

Find the discriminant of the following quadratic equation: $3x^{2} - 12x + 16 = 0$.

Solve the following equation by using the quadratic formula,if the equation has a solution in $R$: $x^{2}-3x-4=0$.

If the following quadratic equation has two equal and real roots,then find the value of $k$: $3x^{2} - 18x + k = 0$.

Solve the following quadratic equation using the quadratic formula,if the equation has a solution in $R$: $5x^{2} + 8x + 3 = 0$.

Examine whether the following equation is quadratic or not: $x(x+1)+8=(x+2)(x-2)$

Vedclass Test Series

Exam Paper Generator

Online Exam Module