Examine whether the following equation is qua | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) quadratic equation in the variable $x$ is an equation of the form $ax^{2} + bx + c = 0$,where $a, b, c$ are real numbers and $a 
eq 0$. In the gi

Vedclass · Accepted Answer

No,it is not a quadratic equation.

Vedclass · Answer

(B) quadratic equation in the variable $x$ is an equation of the form $ax^{2} + bx + c = 0$,where $a, b, c$ are real numbers and $a 
eq 0$. In the given equation $x^{2} + 5\sqrt{x} - 7 = 0$,the term $5\sqrt{x}$ can be written as $5x^{1/2}$. Since the exponent of the variable $x$ is $1/2$,which is not a non-negative integer,this equation is not a polynomial equation of degree $2$. Therefore,it is not a quadratic equation.

Examine whether the following equation is quadratic or not: $x^{2} + 5\sqrt{x} - 7 = 0$.

Similar Questions

State whether the quadratic equation $\sqrt{2} x^{2}-\frac{3}{\sqrt{2}} x + \frac{1}{\sqrt{2}} = 0$ has two distinct real roots. Justify your answer.

Obtain the roots of the following quadratic equation by using the quadratic formula: $9x^{2} + 7x - 2 = 0$.

Divide $29$ into two parts such that the sum of their squares is $425$.

The roots of $x^{2}+12x+36=0$ are ...........

Solve the following equation using the quadratic formula,if the equation has a solution in $R$: $\frac{1}{x+1} + \frac{2}{x+2} = \frac{4}{x+4}; \, x \neq -1, -2, -4$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module