Examine whether the following equation is qua | vedclass

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Question

(B) Given equation: $x + \frac{1}{x} = x^2$ $(x 
eq 0)$.Multiply the entire equation by $x$ to eliminate the fraction:$x(x) + x(\frac{1}{x}) = x(x^2)

Vedclass · Accepted Answer

No,it is not a quadratic equation.

Vedclass · Answer

(B) Given equation: $x + \frac{1}{x} = x^2$ $(x 
eq 0)$.Multiply the entire equation by $x$ to eliminate the fraction:$x(x) + x(\frac{1}{x}) = x(x^2)$$x^2 + 1 = x^3$Rearranging the terms to one side:$x^3 - x^2 - 1 = 0$.$A$ quadratic equation is defined as an equation of the form $ax^2 + bx + c = 0$,where $a 
eq 0$. The highest power (degree) of the variable $x$ in the given equation is $3$. Since the degree of the equation is $3$,it is a cubic equation,not a quadratic equation.

Examine whether the following equation is quadratic or not: $x + \frac{1}{x} = x^2$ $(x \neq 0)$

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