(A) We have $(104)^{3} = (100 + 4)^{3}$.Using the algebraic identity $(x + y)^{3} = x^{3} + y^{3} + 3xy(x + y)$,where $x = 100$ and $y = 4$:$(100 + 4)

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(A) We have $(104)^{3} = (100 + 4)^{3}$.Using the algebraic identity $(x + y)^{3} = x^{3} + y^{3} + 3xy(x + y)$,where $x = 100$ and $y = 4$:$(100 + 4)^{3} = (100)^{3} + (4)^{3} + 3(100)(4)(100 + 4)$$= 1000000 + 64 + 1200(104)$$= 1000000 + 64 + 124800$$= 1124864$.