નિશ્ચિત સંકલન $\int_{0}^{1} \frac{dx}{\sqrt{1+x}-\sqrt{x}}$ ની કિંમત શોધો.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(D) ધારો કે $I = \int_{0}^{1} \frac{dx}{\sqrt{1+x}-\sqrt{x}}$.
છેદનું સંમેયીકરણ કરતા:
$I = \int_{0}^{1} \frac{1}{(\sqrt{1+x}-\sqrt{x})} \times \frac{(\sqrt{1+x}+\sqrt{x})}{(\sqrt{1+x}+\sqrt{x})} dx$
$I = \int_{0}^{1} \frac{\sqrt{1+x}+\sqrt{x}}{(1+x)-x} dx$
$I = \int_{0}^{1} (\sqrt{1+x} + \sqrt{x}) dx$
$I = \left[ \frac{2}{3}(1+x)^{3/2} \right]_{0}^{1} + \left[ \frac{2}{3}x^{3/2} \right]_{0}^{1}$
$I = \frac{2}{3} \left[ (1+1)^{3/2} - (1+0)^{3/2} \right] + \frac{2}{3} [1^{3/2} - 0^{3/2}]$
$I = \frac{2}{3} [2^{3/2} - 1] + \frac{2}{3} [1]$
$I = \frac{2}{3} (2\sqrt{2} - 1) + \frac{2}{3}$
$I = \frac{4\sqrt{2}}{3} - \frac{2}{3} + \frac{2}{3} = \frac{4\sqrt{2}}{3}$.

Explore More

Similar Questions

જો $f : R \to R$ એ એક સતત વિધેય હોય કે જેથી $f(x) = \int\limits_1^x {tf(t)dt}$ થાય,તો નીચેનામાંથી કયું વિધાન સાચું છે?

જો $\int_0^1 \frac{1}{\sqrt{3+x}+\sqrt{1+x}} d x=a+b \sqrt{2}+c \sqrt{3}$,જ્યાં $a, b, c$ સંમેય સંખ્યાઓ છે,તો $2 a+3 b-4 c$ ની કિંમત શોધો:

$\mathop \smallint \limits_0^\pi \sqrt {1 + 4{{\sin }^2}\frac{x}{2} - 4\sin \frac{x}{2}} \;dx = $

$\int_0^{b - c} f''(x + a) \, dx = $

$\int_0^1 (1 + e^{-x^2}) \,dx$ નું મૂલ્ય શું છે?

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo