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(A) To evaluate $93 	imes 95$ without direct multiplication,we can use the algebraic identity $(x + a)(x + b) = x^2 + (a + b)x + ab$.We can express t

Vedclass · Accepted Answer

$8835$

Vedclass · Answer

(A) To evaluate $93 	imes 95$ without direct multiplication,we can use the algebraic identity $(x + a)(x + b) = x^2 + (a + b)x + ab$.We can express the numbers as:$93 = 90 + 3$$95 = 90 + 5$Now,substitute these into the identity where $x = 90$,$a = 3$,and $b = 5$:$(90 + 3)(90 + 5) = (90)^2 + (3 + 5)(90) + (3 	imes 5)$Calculate each term:$(90)^2 = 8100$$(3 + 5)(90) = 8 	imes 90 = 720$$(3 	imes 5) = 15$Adding these values together:$8100 + 720 + 15 = 8835$Therefore,$93 	imes 95 = 8835$.

Evaluate the following product without multiplying directly:
$93 \times 95$

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Evaluate the following product without multiplying directly:$93 \times 95$