Explore More

Similar Questions

The number of all four-digit numbers which begin with $4$ and end with either $0$ or $5$ is:

In how many ways can $6$ examination papers be arranged so that the best and the worst papers are never together?

Difficult
View Solution

Assuming that no two consecutive digits are same,the number of $n$-digit numbers is:

Difficult
View Solution

If $^{12}P_r = 1320$,then $r$ is equal to

By using the non-zero digits,the number of $5$ digit numbers that can be formed such that each number has the largest digit in its middle place and the digits in the number are distinct is:

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo