Ethylidene dichloride is obtained by the reaction of excess of $HCl$ with

Which hydrocarbon reacts with sodium in liquid ammonia?

$CH \equiv CH \mathop {\xrightarrow{Ni(CN)_2}}\limits_{Pressure} X$. Here,$X$ in the reaction is:

Consider the following transformations of a compound $P$ $(C_9H_{12})$:
$(i)$ $P \xrightarrow{NaNH_2, C_6H_5COCH_3, H_3O^+/\Delta} R$ (Optically active)
(ii) $P \xrightarrow{Pt/H_2} \text{propylcyclohexane}$
(iii) $P \xrightarrow{X, KMnO_4/H_2SO_4/\Delta} Q$ ($C_8H_{12}O_6$,Optically active acid)
Choose the correct option$(s)$:
$(A)$ $P$ is $3-$cyclohexylprop$-1-$yne
$(B)$ $X$ is $Pd-C/\text{quinoline}/H_2$
$(C)$ $P$ is $1-$cyclohexylprop$-2-$yne
$(D)$ $R$ is $1-$cyclohexyl$-4-$phenylbut$-3-$yn$-2-$ol

Predict the product $C$ obtained in the following reaction of but$-1-$yne: $CH_3-CH_2-C \equiv CH + HCl \to B \xrightarrow{HCl} C$

$2-$butyne is reduced to $trans-but-2-ene$ using: