Ethanoic acid undergoes Hell-Volhard Zelinsky reaction but methanoic acid does not,because of

  • A
    presence of $\alpha-H$ atom in ethanoic acid
  • B
    absence of $\alpha-H$ atom in ethanoic acid
  • C
    higher acidic strength of ethanoic acid than methanoic acid
  • D
    presence of $\alpha-H$ atom in methanoic acid

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