The equivalent weight of a bivalent metal is | vedclass

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(C) The equivalent weight of a bivalent metal is given as $37.2$. Since the metal is bivalent,its valency is $2$. The atomic weight of the metal is ca

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$145.4$

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(C) The equivalent weight of a bivalent metal is given as $37.2$. Since the metal is bivalent,its valency is $2$. The atomic weight of the metal is calculated as: $	ext{Atomic weight} = 	ext{Equivalent weight} 	imes 	ext{Valency} = 37.2 	imes 2 = 74.4$. The formula of its chloride is $MCl_2$. The molecular weight of $MCl_2$ is: $	ext{Atomic weight of } M + 2 	imes 	ext{Atomic weight of } Cl = 74.4 + 2 	imes 35.5 = 74.4 + 71.0 = 145.4$.

Isotope	Natural abundance (%)	Molar mass $(u)$
$^{35}Cl$	$75.77$	$34.9689$
$^{37}Cl$	$24.23$	$36.9659$

The equivalent weight of a bivalent metal is $37.2$. The molecular weight of its chloride is

Similar Questions

Calculate the average atomic mass of chlorine using the following data:

Isotope Natural abundance (%) Molar mass $(u)$

$^{35}Cl$ $75.77$ $34.9689$

$^{37}Cl$ $24.23$ $36.9659$
(in $u$)

Assertion : The normality of $0.3 \ M$ aqueous solution of $H_3PO_3$ is equal to $0.6 \ N$.
Reason : Equivalent weight of $H_3PO_3 = \frac{\text{Molecular weight of } H_3PO_3}{3}$

$74.5 \ g$ of a metallic chloride contains $35.5 \ g$ of chlorine. The equivalent mass of the metal is

Write formulas for the following compounds:
$(1)$ Iron $(III)$ sulphate
$(2)$ Chromium $(III)$ oxide

In the standardization of $Na_2S_2O_3$ using $K_2Cr_2O_7$ by iodometry,the equivalent weight of $K_2Cr_2O_7$ is:

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