Equivalent weight of H_3PO_2 when it dispropo | vedclass

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(D) The disproportionation reaction is: $3H_3PO_2 \rightarrow PH_3 + 2H_3PO_3$. In this reaction,the oxidation state of $P$ in $H_3PO_2$ is $+1$. It i

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$3M/4$

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(D) The disproportionation reaction is: $3H_3PO_2 \rightarrow PH_3 + 2H_3PO_3$. In this reaction,the oxidation state of $P$ in $H_3PO_2$ is $+1$. It is oxidized to $H_3PO_3$ (where $P$ is $+3$) and reduced to $PH_3$ (where $P$ is $-3$). Change in oxidation state for oxidation: $3 - 1 = 2$. Change in oxidation state for reduction: $1 - (-3) = 4$. For a disproportionation reaction,the equivalent weight $E$ is given by $E = E_{ox} + E_{red} = M/n_{ox} + M/n_{red}$. Here,$n_{ox} = 2$ and $n_{red} = 4$. Therefore,$E = M/2 + M/4 = (2M + M)/4 = 3M/4$.

Equivalent weight of $H_3PO_2$ when it disproportionates into $PH_3$ and $H_3PO_3$ is

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