The equivalent weight of H_2O_2 is: | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The equivalent weight of a substance is calculated as the molar mass divided by the $n$-factor.For $H_2O_2$,the molar mass is $2 	imes 1 + 2 	im

Vedclass · Accepted Answer

$17$

Vedclass · Answer

(A) The equivalent weight of a substance is calculated as the molar mass divided by the $n$-factor.For $H_2O_2$,the molar mass is $2 	imes 1 + 2 	imes 16 = 34 \ g/mol$.In redox reactions,$H_2O_2$ acts as an oxidizing or reducing agent,typically involving a change in oxidation state of oxygen from $-1$ to $-2$ or $0$,resulting in an $n$-factor of $2$.Therefore,the equivalent weight = $\frac{	ext{Molar mass}}{n	ext{-factor}} = \frac{34}{2} = 17$.

The equivalent weight of $H_2O_2$ is:

Similar Questions

In which of the following reactions does $H_2O_2$ act as a reductant?

$H_2O_2$ reduces $K_4[Fe(CN)_6]$ in which of the following conditions?

How does $H_2O_2$ behave as a bleaching agent?

The oxidation states of the most electronegative element in the products of the reaction of $BaO_2$ with dilute $H_2SO_4$ are

The concentration of commercial $H_2O_2$ is $3.125 \ M$,then its grade is $..........$ volume.

Vedclass Test Series

Exam Paper Generator

Online Exam Module