The equivalent weight of FeS_2 in the reactio | vedclass

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(B) To find the equivalent weight,we determine the change in oxidation state of $FeS_2$ in the reaction $FeS_2 	o Fe_2O_3 + SO_2$.In $FeS_2$,the oxid

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$M/11$

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(B) To find the equivalent weight,we determine the change in oxidation state of $FeS_2$ in the reaction $FeS_2 	o Fe_2O_3 + SO_2$.In $FeS_2$,the oxidation state of $Fe$ is $+2$ and $S$ is $-1$ (as $S_2^{2-}$).In $Fe_2O_3$,the oxidation state of $Fe$ is $+3$.In $SO_2$,the oxidation state of $S$ is $+4$.Change in oxidation state of $Fe$: $1 	imes (+3 - (+2)) = +1$.Change in oxidation state of $S$: $2 	imes (+4 - (-1)) = 2 	imes 5 = +10$.Total change in oxidation state (n-factor) = $1 + 10 = 11$.Equivalent weight = $\frac{	ext{Molecular weight}}{	ext{n-factor}} = \frac{M}{11}$.

The equivalent weight of $FeS_2$ in the reaction $FeS_2 \to Fe_2O_3 + SO_2$ is (where $M$ is the molecular weight of $FeS_2$):

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