Enthalpy of fusion and enthalpy of vaporization for water respectively are $6.01 \ kJ \ mol^{-1}$ and $45.07 \ kJ \ mol^{-1}$ at $0^{\circ}C$. What is enthalpy of sublimation at $0^{\circ}C$?

  • A
    $27.50 \ kJ \ mol^{-1}$
  • B
    $48.07 \ kJ \ mol^{-1}$
  • C
    $51.08 \ kJ \ mol^{-1}$
  • D
    $39.06 \ kJ \ mol^{-1}$

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Similar Questions

Match the following terms in Column-$I$ with their corresponding descriptions in Column-$II$:
Column-$I$Column-$II$
$(a)$ Adiabatic process$(1)$ Heat
$(b)$ Isolated system$(2)$ At constant volume
$(c)$ Isothermal change$(3)$ First law of thermodynamics
$(d)$ Path function$(4)$ No exchange of matter and energy
$(e)$ State function$(5)$ No heat exchange
$(f)$ $\Delta U = q$$(6)$ Constant temperature
$(g)$ Law of conservation of energy$(7)$ Internal energy
$(h)$ Reversible process$(8)$ $p_{ext} = 0$
$(i)$ Free expansion$(9)$ At constant pressure
$(j)$ $\Delta H = q$$(10)$ Infinitely slow process involving multiple equilibrium states
$(k)$ Intensive property$(11)$ Entropy
$(l)$ Extensive property$(12)$ Pressure,$(13)$ Specific heat

$\Delta H$ and $\Delta E$ for the reaction,$Fe_{2}O_{3(s)} + 3H_{2(g)} \rightarrow 2Fe_{(s)} + 3H_{2}O_{(l)}$ at constant temperature are related as

$1 \ mol$ of $NH_3$ $(\gamma = 4/3)$ gas at $27 \ ^\circ C$ is expanded under reversible adiabatic conditions to make the volume $8$ times. Calculate the work done in $cal$.

Match the transformations in Column-$I$ with the appropriate options in Column-$II$.
Column-$I$ Column-$II$
$(A) \; CO_{2(s)} \to CO_{2(g)}$ $(p) \; \text{Transition state}$
$(B) \; CaCO_{3(s)} \to CaO_{(s)} + CO_{2(g)}$ $(q) \; \text{Allotropic change}$
$(C) \; 2H^{\cdot} \to H_{2(g)}$ $(r) \; \Delta H > 0$
$(D) \; P_{\text{(white solid)}} \to P_{\text{(red solid)}}$ $(s) \; \Delta S > 0$
$(t) \; \Delta S < 0$

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Calculate $\Delta H^{\circ}$ for the reaction,$Na_2O_{(s)} + SO_{3(g)} \longrightarrow Na_2SO_{4(s)}$,given the following reactions:
$(A) \ Na_{(s)} + H_2O_{(l)} \longrightarrow NaOH_{(s)} + \frac{1}{2}H_{2(g)} \quad \Delta H^{\circ} = -146 \ kJ$
$(B) \ Na_2SO_{4(s)} + H_2O_{(l)} \longrightarrow 2NaOH_{(s)} + SO_{3(g)} \quad \Delta H^{\circ} = +418 \ kJ$
$(C) \ 2Na_2O_{(s)} + 2H_{2(g)} \longrightarrow 4Na_{(s)} + 2H_2O_{(l)} \quad \Delta H^{\circ} = +259 \ kJ$

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