Energy stored in a coil of self-inductance $40 \, mH$ carrying a steady current of $2 \, A$ is.....$J$

$A$ coil has an inductance of $2 \, H$ and resistance of $4 \, \Omega$. $A$ $10 \, V$ potential difference is applied across the coil. The energy stored in the magnetic field after the current has built up to its equilibrium value will be $.......... \times 10^{-2} \, J$.

In what form is the energy stored in an inductor?

The expression for the magnetic energy per unit volume stored in a solenoid in terms of magnetic field is . . . . . . .

When a current $I$ flows through a coil,it stores the energy $E_1$ in it. Now the current is reduced to $I/2$,the energy stored in the coil becomes $E_2$. The change in the energy is

The magnetic energy stored in an inductor of inductance $4\,\mu H$ carrying a current of $2\,A$ is: