Energy per unit volume for a capacitor having area $A$ and separation $d$ kept at potential difference $V$ is given by
$\frac{Q^{2}}{2 C}$
$\frac{1}{2} C V^{2}$
$\frac{1}{2 \varepsilon_{0}} \frac{V^{2}}{d^{2}} $
$\frac{1}{2} \varepsilon_{0} \frac{V^{2}}{d^{2}}$
A condenser of capacity ${C_1}$ is charged to a potential ${V_0}$. The electrostatic energy stored in it is ${U_0}$. It is connected to another uncharged condenser of capacity ${C_2}$ in parallel. The energy dissipated in the process is
Change $Q$ on a capacitor varies with voltage $V$ as shown in the figure, where $Q$ is taken along the $X$-axis and $V$ along the $Y$-axis. The area of triangle $OAB$ represents
A battery is used to charge a parallel plate capacitor till the potential difference between the plates becomes equal to the electromotive force of the battery. The ratio of the energy stored in the capacitor and the work done by the battery will be
What is energy density ? Writes its formula.
If the charge on a capacitor is increased by $2$ coulomb, the energy stored in it increases by $21\%$. The original charge on the capacitor is....$C$