Class 11ChemistryClassification of Elements and Periodicity in PropertiesExtended or long form of periodic table
MediumElement $E$ belongs to the period $4$ and group $16$ of the periodic table. The valence shell electron configuration of the element,which is just above $E$ in the group is $.....$
- A$3 s^{2} 3 p^{4}$
- B$3 d^{10} 4 s^{2} 4 p^{4}$
- C$4 d^{10} 5 s^{2} 5 p^{4}$
- D$2 s^{2} 2 p^{4}$
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Similar Questions
The Modern Periodic Table is based on the atomic number. Explain this with a table.
Medium
View SolutionWhat is the atomic number of the element with symbol $Uus$?
Assign the position of the element having outer electronic configuration in the periodic table:
$(i)$ $ns^{2} np^{4}$ for $n=3$
$(ii)$ $(n-1)d^{2} ns^{2}$ for $n=4$
$(iii)$ $(n-2)f^{7} (n-1)d^{1} ns^{2}$ for $n=6$
$(i)$ $ns^{2} np^{4}$ for $n=3$
$(ii)$ $(n-1)d^{2} ns^{2}$ for $n=4$
$(iii)$ $(n-2)f^{7} (n-1)d^{1} ns^{2}$ for $n=6$
Medium
View SolutionMatch the elements in List-$I$ with their symbols in List-$II$.
List-$I$
List-$II$
$(1)$ $Unnilbium$
$(A)$ $Db$
$(2)$ $Unnilennium$
$(B)$ $Lr$
$(3)$ $Unnilpentium$
$(C)$ $Mt$
$(4)$ $Unniltrium$
$(D)$ $Bh$
$(E)$ $No$
$(F)$ $Rg$
| List-$I$ | List-$II$ |
| $(1)$ $Unnilbium$ | $(A)$ $Db$ |
| $(2)$ $Unnilennium$ | $(B)$ $Lr$ |
| $(3)$ $Unnilpentium$ | $(C)$ $Mt$ |
| $(4)$ $Unniltrium$ | $(D)$ $Bh$ |
| $(E)$ $No$ | |
| $(F)$ $Rg$ |
Easy
View SolutionIn terms of period and group,where would you locate the element with $Z = 114$?
Medium
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