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(A) When a charged particle of mass $m$ and charge $q$ enters a uniform magnetic field $B$ with a velocity $v$ perpendicular to the field,it undergoes

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same for all electrons

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(A) When a charged particle of mass $m$ and charge $q$ enters a uniform magnetic field $B$ with a velocity $v$ perpendicular to the field,it undergoes circular motion.The magnetic Lorentz force provides the necessary centripetal force: $qvB = \frac{mv^2}{r}$.From this,the radius of the circular path is $r = \frac{mv}{qB}$.The time period $T$ is the time taken to complete one full revolution,given by $T = \frac{2\pi r}{v}$.Substituting the value of $r$: $T = \frac{2\pi (mv/qB)}{v} = \frac{2\pi m}{qB}$.Since $m$,$q$,and $B$ are constants for all electrons in this scenario,the time period $T$ is independent of the speed $v$.Therefore,the time periods of rotation will be the same for all electrons.

Electrons moving with different speeds enter a uniform magnetic field in a direction perpendicular to the field. The time periods of rotation will be:

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