Electronic configurations of four elements $A$,$B$,$C$,$D$ are given below:
$A$) $1s^2 2s^2 2p^6 3s^1$
$B$) $1s^2 2s^2 2p^6 3s^2 3p^1$
$C$) $1s^2 2s^2 2p^6 3s^2$
$D$) $1s^2 2s^2 2p^6 3s^2 3p^2$
The correct order of first ionization enthalpy of these elements is:

  • A
    $D > B > C > A$
  • B
    $C > D > B > A$
  • C
    $C > A > B > D$
  • D
    $D > C > B > A$

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The atomic numbers of elements $X, Y$,and $Z$ are $19, 37$,and $55$ respectively. Which of the following statements is correct?

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Which of the following presents the correct order of second ionization enthalpies of $C$,$N$,$O$ and $F$?

Match List-$I$ with List-$II$:
List-$I$ (Electronic configuration of neutral atom where $n=2$)List-$II$ ($1^{st}$ Ionization Energy in $\text{kJ mol}^{-1}$)
$A. ns^2$$I. 2080$
$B. ns^2np^1$$II. 899$
$C. ns^2np^3$$III. 800$
$D. ns^2np^6$$IV. 1402$

Which particle may be removed from a stable neutral atom with the least energy change?

For which of the following reactions is the $\Delta H^o$ value equal to the first ionization energy of $Ca$?

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