Electric potential at any point is $V = - 5x + 3y + \sqrt {15} z$, then the magnitude of the electric field is
$3\sqrt 2 $
$4\sqrt 2 $
$5\sqrt 2 $
$7$
The electric potential at a point $(x,\;y)$ in the $x - y$ plane is given by $V = - kxy$. The field intensity at a distance $r$ from the origin varies as
Variation of electrostatic potential along $x$-direction is shown in the graph. The correct statement about electric field is
The electric potential $V(x)$ in a region around the origin is given by $V(x) = 4x^2\,volts$ . The electric charge enclosed in a cube of $1\,m$ side with its centre at the origin is (in coulomb)
Electric potential at any point is $V = -5x + 3y + \sqrt {15} z$, then the magnitude of the electric field is
The electrostatic potential inside a charged spherical ball is given by $\phi= a{r^2} + b$ where $r$ is the distance from the centre and $a, b$ are constants. Then the charge density inside the ball is: