Each nuclear fission of {}^{235}U releases 20 | vedclass

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Question

(A) The energy released per fission is $E = 200 	ext{ MeV}$.Converting this to Joules: $E = 200 	imes 10^6 	imes 1.6 	imes 10^{-19} 	ext{ J} = 3.

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$3.125 	imes 10^{16}$

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(A) The energy released per fission is $E = 200 	ext{ MeV}$.Converting this to Joules: $E = 200 	imes 10^6 	imes 1.6 	imes 10^{-19} 	ext{ J} = 3.2 	imes 10^{-11} 	ext{ J}$.The power generated by the reactor is $P = 1 	ext{ MW} = 10^6 	ext{ W} = 10^6 	ext{ J/s}$.The rate of fission $R$ is given by the formula $R = P / E$.$R = 10^6 / (3.2 	imes 10^{-11}) = (1 / 3.2) 	imes 10^{17} = 0.3125 	imes 10^{17} = 3.125 	imes 10^{16} 	ext{ fissions/s}$.

Each nuclear fission of ${}^{235}U$ releases $200 \text{ MeV}$ of energy. If a reactor generates $1 \text{ MW}$ power,then the rate of fission in the reactor is:

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