During the mean life of a radioactive element | vedclass

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(B) The number of radioactive nuclei remaining after time $t$ is given by $N(t) = N_0 e^{-\lambda t}$.The mean life $	au$ of a radioactive element is

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$\frac{e-1}{e}$

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(B) The number of radioactive nuclei remaining after time $t$ is given by $N(t) = N_0 e^{-\lambda t}$.The mean life $	au$ of a radioactive element is defined as $	au = \frac{1}{\lambda}$.The fraction of nuclei that remains after time $t = 	au$ is $\frac{N}{N_0} = e^{-\lambda 	imes \frac{1}{\lambda}} = e^{-1} = \frac{1}{e}$.The fraction that disintegrates is $1 - \frac{N}{N_0} = 1 - \frac{1}{e} = \frac{e-1}{e}$.

During the mean life of a radioactive element,the fraction that disintegrates is

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