During $S$ estimation,$160 \ mg$ of an organic compound gives $466 \ mg$ of barium sulphate. The percentage of Sulphur in the given compound is . . . . . . $\%.$ (Given molar mass in $g \ mol^{-1}$ of $Ba: 137, S: 32, O: 16$)

  • A
    $39$
  • B
    $40$
  • C
    $41$
  • D
    $42$

Explore More

Similar Questions

Explain the Carius method and its principle for the estimation of halogen elements.

Difficult
View Solution

Discuss the Dumas method and its principles for the estimation of $N$ present in an organic compound.

What is $CHN$ analysis in organic estimation?

During the estimation of nitrogen present in an organic compound by the Kjeldahl method,the ammonia evolved from $0.5 \ g$ of the compound neutralized $10 \ mL$ of $1 \ M$ $H_{2}SO_{4}$. Find the percentage of nitrogen in the compound. (in $\%$)

In Carius method of estimation of halogen,$0.25 \ g$ of an organic compound gave $0.15 \ g$ of silver bromide $(AgBr)$. The percentage of Bromine in the organic compound is $.......... \times 10^{-1} \%$ ($Nearest$ integer). (Given: Molar mass of $Ag$ is $108 \ g \ mol^{-1}$ and $Br$ is $80 \ g \ mol^{-1}$)

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo