Draw the nature of $V -I$ graph for a nichrome wire. $(V -$ Potential difference, $I -$ Current)

$A$ metallic wire of $625\, mm$ length offers a $4\, \Omega$ resistance. If the resistivity of the metal is $4.8 \times 10^{-7} \,ohm-metre$, then calculate the area of cross$-$ section of the wire.

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The graph is as shown

Given $\quad \rho=4.8 \times 10^{-7} \Omega m$

$L=625 mm =0.625 m , R =4 \Omega, A =?$

Using the expression $R =\frac{\rho L }{ A },$ we have

$A=\frac{\rho L}{R}=\frac{4.8 \times 10^{-7} \times 0.625}{4}$

$=0.75 \times 10^{-7} m ^{2}$

1091-s204

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