Draw the graphs of the pair of linear equatio | vedclass

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(B) To draw the graphs of the given equations,we find two solutions for each equation:For $x-y+2=0$:$x$$0$$-2$$y=x+2$$2$$0$For $4x-y-4=0$:$x$$0$$1$$y=

Vedclass · Accepted Answer

$6$

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(B) To draw the graphs of the given equations,we find two solutions for each equation:For $x-y+2=0$:$x$$0$$-2$$y=x+2$$2$$0$For $4x-y-4=0$:$x$$0$$1$$y=4x-4$$-4$$0$Plot the points $A(0, 2)$,$B(-2, 0)$,$P(0, -4)$,and $Q(1, 0)$ on a graph and draw the lines $AB$ and $PQ$. The lines intersect at point $R(2, 4)$.The triangle formed by these lines and the $x$-axis is $	riangle BQR$,with vertices $B(-2, 0)$,$Q(1, 0)$,and $R(2, 4)$.Area of triangle $= \frac{1}{2} 	imes 	ext{Base} 	imes 	ext{Altitude}$.Here,Base $= BQ = |1 - (-2)| = 3$ units.Altitude $= 	ext{Ordinate of } R = 4$ units.Area $= \frac{1}{2} 	imes 3 	imes 4 = 6$ sq. units.

Draw the graphs of the pair of linear equations $x-y+2=0$ and $4x-y-4=0$. Calculate the area of the triangle formed by the lines so drawn and the $x$-axis (in sq. units).

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